PEP 294: Lecture Notes
Trigonometry & Vector Algebra
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Trigonometry (pp. 504-507)
1. Basic Geometry
| Lines & angles: |
- straight line:
a = 180°
- parallel lines:
a = b = c = d
| Triangles: |
- regular triangle:
3 sides & 3 angles
a + b + c = 180°- right-angled triangle:
c = 90°
a + b + c = 180°
a + b = 90° => b = a - 90°
C = hypotenuse
A = opposite of a (or adjacent of b)
B = adjacent of a (or opposite of b)
Pythagorean theorem:
- Example: A = 3 & B = 4. Compute C.
2. Trigonometric Functions
| Definitions: |
SOH CAH TOA!
| Properties: |
=>
| Example 1: For the right triangle above, A = 3 & B = 4. Compute the following. |
- From the Pythagorean theorem:
C =
- Therefore:
cos a =
sin a =
tan a =
cos b =
sin b =
tan b =
(Use 3 decimal places for the trig function values.)
Example 2 (use a calculator)
sin 30° =
cos 60° =
tan 60° =
(Use 3 decimal places for the trig function values.)
| Inverse functions: |
- known function value => compute angle
sin a = x => a = sin-1(x), -90° < a < 90°
cos a = x => a = cos-1(x), 0° < a < 180°
tan a = x => a = tan-1(x), -90° < a < 90°
- Examples:
sin a = 0.643 => a = sin-1( 0.643 ) =
cos a = 0.921 => a =
tan a = 1.483 => a =
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Vector Algebra (pp. 76-81)
1. Vector vs. Scalar Quantity
| Displacement vs. distance: |
- moving from A to B (Path 1 or 2)
- distance:
(a) length of the path (magnitude)
(b) varies depending on the path (1 or 2)
(c) scalar: magnitude only
- displacement:
(a) length of straight path from A to B (magnitude) + NE (direction)
(b) net effect of motion
(c) path-independent (1 = 2)
(d) vector: magnitude + direction
| Vector |
- magnitude + direction
- examples: displacement, position, velocity, force, momentum .
- a (bold) or
(arrow)
- vector arrow:
(a) length of the arrow: magnitude
(b) tip: direction
| Vector example: force |
- differences in magnitude and direction of the force result in different motions of the ball
2. Vector Algebra
| Vector addition: |
- displacement vectors
| The "Tip-To-Tale Method": the graphical approach |
- connect all vectors, one by one, tip to tail
- move vectors freely while keeping direction and magnitude
- sequence of addition is not important
| Vector resolution: |
- resolution: breaking down of a vector into components
a => aX + aY
- aX & aY: components:
- Example: Soccer kick, velocity = 20 m/s, q = 35° --> vH, vV ?
vH = v·cosq = (20)(cos 35°) = 16.38 m/s
vV = v·sinq = (20)(sin 35°) = 11.47 m/s
| Vector composition: |
- composition: construction of a vector from its components
aX + aY => a
- Example (Sample problem 2 on p. 302): vswim = 2 m/s, vcurrent = 0.5 m/s --> v, q = ?
v =
= 1.62 m/s
q = tan-1
= 14.04°
| Vector addition: the component approach |
- Let C = A + B, then
Cx = Ax + Bx
Cy = Ay + By
- Sequences:
(a) Compute the components of A and B through vector resolution. (Pat attention to the directions of the components.)
(b) Compute the components of C (Cx and Cy).
(c) Compute the magnitude (C) and the direction (q) of C through vector composition.
- Example:
Displacements of an orienteer: 400m E + 500 m NE
Ax = 400, Ay = 0
Bx = (500)(cos45°) = 353.50
By = (500)(sin45°) = 353.50
Cx = Ax + Bx = 400 + 353.50 = 753.50
Cy = Ay + By = 0 + 353.50 = 353.50
C =
q =
Ans: 832.30 m (25.13° N of due E)